melindamackay83 melindamackay83
  • 04-01-2019
  • Mathematics
contestada

At the pet fair Darlene’s dog weighed five times as much as leaders dog. Together the dogs weighed 84 pounds how much did each dog weigh?

Respuesta :

musiclover10045
musiclover10045 musiclover10045
  • 04-01-2019

Answer:

Let the weight of the leader dog = X

Then Darlene's dog weighs = 5X ( fives times as much)

Now add both together to equal 84 pounds:

5X + X = 84


Simplify:

6x = 84

Divide both sides by 6:

x = 84 / 6

x = 14


The leader dog weighs 14 pounds.

Darlene's dog weighs 70 pounds.


Answer Link

Otras preguntas

what is contract theory
civil war: What advantages did the North have over the South in this war? What advantage did the South have? Explain each.
5+2+4+6+7-9+8-0+9-3=
SOMEONE WHO SPEAKS SPANISH OR IS GOOD AT SPANISH PLEASE HELP!! Parte A- Create a 5 sentence conversation for each image below: Parte B- Write two different advi
Please help I'll mark you as brainiest
Find the surface area of the square pyramid shown below. ​
What is the gravitational potential energy of a 2.5 kg object that is 300 m above the surface of the earth
¿Cuáles fueron los principales Estados coloniales y con qué objetivo emprendían la ocupación de territorios de ultramar?
what are some examples of human-made resources​
A 40% off sale' begins today at Wanda's Women's Wear. What is the sale price of women's wool coats normally priced at $290?