Respuesta :

a5904640

[tex]\frac{dy}{dx}=\frac{1}{5}.x^{2-1}.2 + \frac{1}{11}.x^{1-1}.1[/tex]

[tex]\frac{dy}{dx}=\frac{2}{5}.x+\frac{1}{11}[/tex]

[tex]\frac{d^2y}{dx^2}=\frac{2}{5}.x^{1-1}.1[/tex]

[tex]\frac{d^2y}{dx^2}=\frac{2}{5}[/tex]