kamikathegreat3836 kamikathegreat3836

02-03-2020
Chemistry

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What is the escape speed for an electron initially at rest on the surface of a sphere with a radius of 1.0 cm and a uniformly distributed charge of 1.91 ×10-15 C

Respuesta :

mshahzaib247 mshahzaib247

04-03-2020

Answer:

v = 22492 ms^-1

Explanation:

[tex]1/2 m v^2 = kqQ / r[/tex]

[tex]v = \sqrt{2kqQ / rm}[/tex]

[tex]v = \sqrt{2*(9*10^9)*(1.6*10^-19)*(1.6 * 10^-15) / (0.01)*(9.109*10^-31)}[/tex]

v = 22492 ms^-1

v = 22.492 k ms^-1

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