[tex]2x\sqrt{40x}-2x\sqrt{5}[/tex] is found by first, siplifying the radicals in the parenthesis. [tex]\sqrt{8x^{2} }[/tex] can be simplified as [tex]2x\sqrt{2}[/tex] and [tex]-2\sqrt{x}[/tex] stays the same. Now we have to multiply these two by [tex]\sqrt{5x}[/tex] which then results in [tex]2x\sqrt{40x}-2x\sqrt{5}[/tex]
