Boxhead234 Boxhead234

02-09-2020
Mathematics

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find the x and y intercepts of the circle: (x-6)^2+(y+3)^2=16

find the x and y intercepts of the circle x62y3216 class=

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s650705 s650705

02-09-2020

Answer: x=0 y=2

Step-by-step explanation:

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46558957 46558957

02-09-2020

Answer:

-y+11

Step-by-step explanation:

(x-6)•2+(y+3)•2-(y+3)•2=16-(y+3)•2

(x-6)•2=-2y+10

(x-6)•=-2y/2+10/2

x-6=-y+5

x=-y+11

Answer Link

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