How many solutions exist for 2|x − 1| = 8?

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vpohl1 vpohl1 · Answer 1 · 2020-09-04T05:29:50+02:00

two solutions exist,
2(x - 1) = 8
2x - 2 = 8
2x = 10
x = 5
&
2(x + 1) = 8
2x + 2 = 8
2x = 6
x = 3

the two solutions are 5 and 3

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smecloudbird18 smecloudbird18 · Answer 2 · 2022-06-16T17:07:27+02:00

The two solutions of the equation are 7 and -5

It is an assignment of value to the unknown variables that make the equality in the equation true

2|x − 1| = 8

| x-1 | = 6

mod mean only positive of that number , when it is removes negative of that will also considered

there will exist two solutions of that equation

1 ) x-1 =6

x= 7

2) -(x-1) =6

-x + 1 =6

x = -5

The two solutions of the equation are 7 and -5

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