Respuesta :

Given that the pressure in the whole process is constant, we could use the Charles's law:

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

Let's replace our values and solve the equation for T2:

[tex]\frac{623mL}{137C}=\frac{914mL}{T_2}\to T_2=\frac{137C\cdot914mL}{623mL}=201C[/tex]

The temperature of the gas sample will be 201°C.

Otras preguntas