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Block A, with a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B , with a mass of 8.0 kg, is moving in the opposite direction with a speed of 3.0 m/s. The center of mass of the two block system is moving with velocity of?

Respuesta :

Consider velocity to the right as positive.

First mass:
m₁ = 4.0 kg
v₁ = 2.0 m/s to the right

Second mass:
m₂ = 8.0 kg
v₂ = -3.0 m/s to the left

Total momentum of the system is
P = m₁v₁ + m₂v₂
   = 4*2 + 8*(-3)
  = -16 (kg-m)/s

Let v (m/s) be the velocity of the center of mass of the 2-block system.

Because momentum of the system is preserved, therefore
(m₁+m₂)v= -16
(4+8 kg)*(v m/s) = -16 (kg-m)/s
v = -1.333 m/s

Answer:
The center of mass is moving at 1.33 m/s to the left.
okpalawalter8

We have that the velocity  two block system   is mathematically given as

vcm= -16 m/s

Velocity  two block system

Question Parameters:

With a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B , with a mass of 8.0 kg, is moving in the opposite direction with a speed of 3.0 m/s.

Generally the equation for the Velocity   is mathematically given as

vcm = (m1*v1) + (m2*v2)

vcm = ((4*2)-(8*3))

vcm= -16 m/s

And the direction is

dcm = in the direction of block B

For more information on Velocity visit

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