A horse is pulling 53.0 kg plow forward while the ground exerts a 275 N force, and the plow accelerates at 0.222 m/s^2. what is the magnitude(+) of the force the ground exerts on the plow?
Answer: Magnitude of force the ground exerts on the plow = 263.234 N
Explanation: Magnitude of force the ground exerts on the plow = Fground - Fplow We are given that: Fgound = 275 N We will now calculate Fplow as follows: Fplow = mass of horse * acceleration of plow Fplow = 53 * 0.222 Fplow = 11.766 N
Now, substitute in the above equation to get magnitude of force the ground exerts on the plow as follows: Magnitude of force the ground exerts on the plow = Fground - Fplow Magnitude of force the ground exerts on the plow = 275 - 11.766 Magnitude of force the ground exerts on the plow = 263.234 N
